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cubixguy77

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27 12 Identical Balls

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12 Identical Balls
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12 Identical Balls

I found an alternate solution to this one: The first step is the same, but in step 2, when you've got 1-4 and 5-8 as containing the odd one out, weigh (1,2,5) x (3,4,9). If they're equal, then 6,7,or 8 is the light one, so weigh one against another. Otherwise, there are two outcomes: 1) if (1,2,5) is lighter, then either (1,2) is heavy, or 5 is light, so weigh (1) x (2). 2) if (1,2,5) is heavier, then either (1,2) is heavy, so again weigh (1) x (2) to find out which.

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