Charlie once visited chocolate factory to buy some chocolates.Chocolate cost Rs. 3 each and he had only Rs. 45.He was disappointed. He wanted more. But when he reached the factory he was amazed. There was a scheme on that special day. If you return 3 wrappers of the chocolate you will get one chocolate for free. So how many chocolates can he buy?
Charlie has Rs. 45 and each chocolate cost Rs. 3. So he buys only 15. But there is a scheme. He will return 15 wrappers and get 5 chocolates free. Then he will return 3 out of 5 and get one free. And he will again use one wrapper with the remaining 2 to get one more.
So 15+5+1+1 = 22.
Comments
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Answer should be 15. The question is how many chocolates can he buy right? 22 is so wrong!!!
It would help if the questio were rephrased to read "How many chocolates can he GET?"
First he buys 15, then ...
ju
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IT WAS VERY SIMPLE WATCH THIS
https://youtu.be/tWztTPvtVbo
22 and 1 wrapper left
15 chocolates from 45 Rs. generates 15 wrappers => 5 more chocolates generates 5wrappers => 1 more chocolate + 2 wrappers generates 1 more wrapper => 3 wrappers=> 1 more chocolate 1 wrapper left
Urvesh, there's a Show Solution button to check if your solution is correct!
yep! forgot to see that. . . :P
Nice to find a formula for the general case whereas there's 'n' instead of '45'...
Sum of (n/3^i) from i = 0 to i = ∞ But it gives 22.5 for 45
The formula is incorrect ... It assumes that money and wrappers can be used together to buy new chocolate
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Total: 22
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22 actually.. didn't realize in end he will have 2 wrappers + 1 chocolate => 3 chocolates..
its -: 15+5+1+1
22 Chocolates And 1 wrapper is left
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22 chocolates and 1 wrapper left
How about this?
good one just needs patience.
Actually, he can only buy 15 chocolates...the others are free.
A ruby solution. You could also build in different wrapper trade in ratios or different costs of chocolate bars.
class Buyer attrreader :chocbars def initialize(cash = 45, choc_bars = 0)
end
def getdatchocolate
end
private def tradeinwrappers
end
def spend_monies
end end
x = Buyer.new x.getdatchocolate
The real answer should be 15... He can only BUY 15.. the last 7 he got free for trading in wrappers.
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He can only BUY 15. The other 7 he gets are free as per the parameters of the question.
Rs. 45 = Rs.3 * 15 Chocolates 15 Chocolates = 15 Wrappers 3 Wrappers = 1 Chocolate 15 Wrappers = 5 Chocolates.. so totally 20 CHOCOLATES...!!!
Rs. 45 = Rs.3 * 15 Chocolates 15 Chocolates = 15 Wrappers 3 Wrappers = 1 Chocolate 15 Wrappers = 5 Chocolate(3 Wrappers = 1 Chocolates.)..
15+5+1+1=22 so totally 22 CHOCOLATES...!!!
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